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What will be the output of the following C++ code?
#include<iostream>
using namespace std;
class Test
{
protected:
int x;
public:
Test (int i):x(i) { }
void fun() const { cout << "fun() const " << endl; }
void fun() { cout << "fun() " << endl; }
};
int main()
{
Test t1 (10);
const Test t2 (20);
t1.fun();
t2.fun();
return 0;
}
using namespace std;
class Test
{
protected:
int x;
public:
Test (int i):x(i) { }
void fun() const { cout << "fun() const " << endl; }
void fun() { cout << "fun() " << endl; }
};
int main()
{
Test t1 (10);
const Test t2 (20);
t1.fun();
t2.fun();
return 0;
}
- a)fun()
fun() const - b)fun() const
fun() - c)fun()
fun() - d)fun() const
fun() const
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
What will be the output of the following C++ code?#include<iostream...
Explanation:
- Class Test:
- The class Test has a protected integer variable x and two member functions named fun().
- The constructor initializes the value of x with the passed argument.
- Main Function:
- Two objects t1 and t2 of class Test are created with values 10 and 20 respectively.
- The object t1 calls the non-const version of the fun() function, printing "fun() ".
- The object t2 calls the const version of the fun() function, printing "fun() const".
- Output:
- When t1.fun() is called, it prints "fun() ".
- When t2.fun() is called, it prints "fun() const".
Therefore, the output of the code will be:
fun()
fun() const
- Class Test:
- The class Test has a protected integer variable x and two member functions named fun().
- The constructor initializes the value of x with the passed argument.
- Main Function:
- Two objects t1 and t2 of class Test are created with values 10 and 20 respectively.
- The object t1 calls the non-const version of the fun() function, printing "fun() ".
- The object t2 calls the const version of the fun() function, printing "fun() const".
- Output:
- When t1.fun() is called, it prints "fun() ".
- When t2.fun() is called, it prints "fun() const".
Therefore, the output of the code will be:
fun()
fun() const
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Community Answer
What will be the output of the following C++ code?#include<iostream...
As the object declared are of two types one is normal object and other is constant object So normal objects calls normal fun() whereas constant objects calls constant fun().
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What will be the output of the following C++ code?#include<iostream>using namespace std;class Test{ protected: int x; public: Test (int i):x(i) { } void fun() const { cout << "fun() const " << endl; } void fun() { cout << "fun() " << endl; }};int main(){ Test t1 (10); const Test t2 (20); t1.fun(); t2.fun(); return 0;}a)fun()fun() constb)fun() constfun()c)fun()fun()d)fun() constfun() constCorrect answer is option 'A'. Can you explain this answer?
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What will be the output of the following C++ code?#include<iostream>using namespace std;class Test{ protected: int x; public: Test (int i):x(i) { } void fun() const { cout << "fun() const " << endl; } void fun() { cout << "fun() " << endl; }};int main(){ Test t1 (10); const Test t2 (20); t1.fun(); t2.fun(); return 0;}a)fun()fun() constb)fun() constfun()c)fun()fun()d)fun() constfun() constCorrect answer is option 'A'. Can you explain this answer? for Class 7 2024 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about What will be the output of the following C++ code?#include<iostream>using namespace std;class Test{ protected: int x; public: Test (int i):x(i) { } void fun() const { cout << "fun() const " << endl; } void fun() { cout << "fun() " << endl; }};int main(){ Test t1 (10); const Test t2 (20); t1.fun(); t2.fun(); return 0;}a)fun()fun() constb)fun() constfun()c)fun()fun()d)fun() constfun() constCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 7 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the output of the following C++ code?#include<iostream>using namespace std;class Test{ protected: int x; public: Test (int i):x(i) { } void fun() const { cout << "fun() const " << endl; } void fun() { cout << "fun() " << endl; }};int main(){ Test t1 (10); const Test t2 (20); t1.fun(); t2.fun(); return 0;}a)fun()fun() constb)fun() constfun()c)fun()fun()d)fun() constfun() constCorrect answer is option 'A'. Can you explain this answer?.
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